trigonometric equations

Hi everyone, this is Pawandeep. Today in class we learned about how to solve trigonometric equations on a specified interval 2. We also had quiz but it was easy only.
NOTE: You should always keep these our things in mind while doing these equations:-
1 SOH CAH TOA rule
2 quadrantal angles
3 CAST rule
4 special triangles

One o the example we did in class is:
2Sin^2=3Sin-1

to solve this first step is to factor the equation;
2Sin^2-3Sin+1=0
2Sin^2-2Sin-1Sin+1=0
2Sin(Sin-1)-1(Sin-1)=0
(2Sin-1)(Sin-1)=0
2Sin-1=0 or Sin-1=0
Sin=1/2 or Sin=1

Now, we have to find the reference angle by using the circle;

as sin is positive in two quadrants;Q1 and Q2
if Sin is 1/2 then,
reference angle is pie/6 or 30 degree
 so Q2:- 2pie-pie/6=5pie/6

if Sin is1 then
reference angle=relative angle=90degree or pie/2

so finally theta=pie/6, pie/2, 5pie/6

this is how we solve these equations............................. :))))